A) glucose
B) fructose
C) sucrose
D) all of these
Correct Answer: A
Solution :
Glucose reduces Fehling solution to give red \[ppt.\] of \[C{{u}_{2}}O\] as: \[\underset{\begin{smallmatrix} | \\ C{{H}_{2}}OH \end{smallmatrix}}{\overset{\begin{smallmatrix} CHO \\ | \end{smallmatrix}}{\mathop{{{(CHOH)}_{4}}}}}\,+\underset{\begin{smallmatrix} Fehling \\ solution \end{smallmatrix}}{\mathop{2Cu{{(OH)}_{2}}}}\,+NaOH\xrightarrow{{}}\] \[\underset{red\,\,ppt.}{\mathop{C{{u}_{2}}O}}\,+\underset{\begin{smallmatrix} | \\ C{{H}_{2}}OH \end{smallmatrix}}{\overset{\begin{smallmatrix} COONa \\ | \end{smallmatrix}}{\mathop{{{(CHOH)}_{4}}}}}\,+3{{H}_{2}}O\] Fructose and sucrose does not respond to Fehling solution.
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