A) \[2x-y\]
B) \[2x+y\]
C) \[x+y\]
D) \[\frac{2x-y}{2}\]
Correct Answer: A
Solution :
Given: \[S+\frac{3}{2}{{O}_{2}}\xrightarrow{{}}S{{O}_{3}}\] \[\Delta n=2x\] ... (i) \[S{{O}_{2}}+\frac{1}{2}{{O}_{2}}\xrightarrow{{}}S{{O}_{3}}\] \[\Delta n=y\] ... (ii) Heat of formation of \[S{{O}_{2}}\] can be calculated by reversing the Eq. (ii) and then adding the Eq. (i) and (iii). \[S{{O}_{3}}\xrightarrow{{}}S{{O}_{2}}+\frac{1}{2}{{O}_{2}}-y\] ... (iii) Now, by adding the Eqs. (i) and (ii) \[S+\frac{3}{2}{{O}_{2}}\xrightarrow{{}}S{{O}_{3}}+2x\] ... (i) \[S{{O}_{3}}\xrightarrow{{}}S{{O}_{2}}+\frac{1}{2}{{O}_{2}}-y\] ... (ii) \[\underline{\overline{S+{{O}_{2}}\xrightarrow{{}}S{{O}_{2}}+(2x-y)}}\] ... (iii) So, heat of formation of \[S{{O}_{2}}\] is\[2x-y\].
You need to login to perform this action.
You will be redirected in
3 sec
