A) \[4\,\,A\]
B) \[1.56\,\,A\]
C) \[5.6\,\,A\]
D) \[1.41\,\,A\]
Correct Answer: C
Solution :
The peak value of current \[({{I}_{0}})\] is given by \[{{I}_{0}}=\sqrt{2}{{I}_{rms}}\] where \[{{I}_{rms}}\]is known as root mean square value of current. Given, \[{{I}_{rms}}=4\,\,A\] \[\therefore \] \[{{I}_{0}}=\sqrt{2}\times 4=5.6\,\,A\]
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