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JCECE Engineering JCECE Engineering Solved Paper-2006

  • question_answer
    If \[f\] is the frequency when mass m is attached to a spring of spring constant \[k\], then new frequency for this arrangement, is:

    A) \[f/2\]                                  

    B) \[\sqrt{2f}\]

    C)  \[f/\sqrt{2}\]                   

    D)  \[2\sqrt{2f}\]

    Correct Answer: B

    Solution :

    Key Idea: The system executes\[SHM\]. The frequency of oscillation of spring mass system is given by                 \[f=\frac{1}{2\pi }\sqrt{\frac{k}{m}}\] For the given arrangement                 \[k'=\frac{1}{2\pi }\sqrt{\frac{k}{m}}\] Hence, frequency of oscillation is                 \[f'=\frac{1}{2\pi }\sqrt{\frac{k'}{m}}\] \[\Rightarrow \]               \[f'=\frac{1}{2\pi }\sqrt{\frac{2k}{m}}=\sqrt{2}f\]


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