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JCECE Engineering JCECE Engineering Solved Paper-2005

  • question_answer
    If\[(-4,\,\,5)\] is one vertex and \[7x-y+8=0\] is one diagonal of a square, then the equation of the second diagonal is:

    A) \[x+3y=21\]                       

    B) \[2x-3y=7\]

    C) \[x+7y=31\]                       

    D) \[2x+3y=21\]

    Correct Answer: C

    Solution :

    Key Idea: In a square two diagonals intersect perpendicularly. Since, equation of one diagonal of a square is \[7x-y+8=0\] \[\therefore \]The equation of another diagonal will be\[x+7y+\lambda =0\]. This diagonal passes through the point\[(-4,\,\,5)\]. \[\therefore \]  \[-4+35+\lambda =0\Rightarrow \lambda =-31\] \[\therefore \]The required diagonal is,                 \[x+7y=31\]


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