JCECE Engineering JCECE Engineering Solved Paper-2005

  • question_answer
    An alternating current is given by\[i={{i}_{1}}\cos \theta t+{{i}_{2}}\sin \omega t\]. The rms current is given by:

    A) \[\frac{{{i}_{1}}+{{i}_{2}}}{\sqrt{2}}\]                     

    B) \[\frac{{{i}_{1}}-{{i}_{2}}}{\sqrt{2}}\]

    C) \[\sqrt{\left( \frac{i_{1}^{2}+i_{2}^{2}}{2} \right)}\]                        

    D) \[\sqrt{\left( \frac{i_{1}^{2}-i_{2}^{2}}{2} \right)}\]

    Correct Answer: C

    Solution :

    The root mean square value of current is given by                 \[{{i}_{rms}}=\sqrt{\frac{i_{1}^{2}+i_{2}^{2}}{2}}\]


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