JCECE Engineering JCECE Engineering Solved Paper-2004

  • question_answer
    \[\int_{8}^{15}{\frac{dx}{(x-3)\sqrt{x+1}}}\]is equal to:

    A) \[\frac{1}{2}\log \frac{5}{3}\]                     

    B) \[\frac{1}{3}\log \frac{5}{3}\]

    C) \[\frac{1}{5}\log \frac{3}{5}\]                     

    D) \[\frac{1}{2}\log \frac{3}{5}\]

    Correct Answer: A

    Solution :

    Key Idea: If Integra; is in the form of\[\int{\frac{dx}{(ax+b)\sqrt{px+q}}}\], then put\[px+q={{t}^{2}}\], Let          \[I=\int_{8}^{15}{\frac{dx}{(x-3)\sqrt{x+1}}}\] Put         \[x+1={{t}^{2}}\Rightarrow dx=2t\,\,dt\] \[\therefore \]  \[I=\int_{3}^{4}{\frac{2t\,\,dt}{({{t}^{2}}-4)t}}=2\int_{3}^{4}{\frac{dt}{{{t}^{2}}-4}}\]                    \[=2\times \frac{1}{2\times 2}\left[ \log \frac{t-2}{t+2} \right]_{3}^{4}\]                   \[=\frac{1}{2}\left( \log \frac{2}{6}-\log \frac{1}{5} \right)\]                  \[=\frac{1}{2}\log \frac{5}{3}\]


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