JCECE Engineering JCECE Engineering Solved Paper-2004

  • question_answer
    \[\frac{{{d}^{3}}y}{d{{x}^{3}}}+\left[ 1+\frac{{{d}^{2}}y}{d{{x}^{2}}} \right]=1\], has degree and order as:

    A) \[3,\,\,1\]                                           

    B) \[3,\,\,2\]

    C) \[1,\,\,3\]                                           

    D) \[2,\,\,3\]

    Correct Answer: C

    Solution :

    We have,\[\frac{{{d}^{3}}y}{d{{x}^{3}}}+2\left[ 1+\frac{{{d}^{2}}y}{d{{x}^{2}}} \right]=1\] \[\therefore \]Degree \[=1\] and order\[=3\]


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