A) \[1:2\]
B) \[2:1\]
C) \[1:1\]
D) \[4:1\]
Correct Answer: A
Solution :
Key Idea: The potential energy of satellite is twice its kinetic energy but opposite in sign. Potential energy, \[U=-\frac{G{{M}_{e}}m}{{{R}_{e}}}\]or\[|U|=\frac{G{{M}_{e}}m}{{{R}_{e}}}\] Kinetic energy, \[K=\frac{1}{2}\frac{G{{M}_{e}}m}{{{R}_{e}}}\] Thus \[\frac{K}{|U|}=\frac{1}{2}\frac{G{{M}_{e}}m}{{{R}_{e}}}\times \frac{{{R}_{e}}}{G{{M}_{e}}m}=\frac{1}{2}\]
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