A) \[6.626\times {{10}^{-35}}m\]
B) \[6.626\times {{10}^{-34}}m\]
C) \[6.626\times {{10}^{-33}}m\]
D) none of these
Correct Answer: A
Solution :
From de-Broglie wavelength \[(\lambda )\], we have \[\lambda =\frac{h}{mv}\] where, \[h\] is Planck's constant, \[m\] is mass and \[v\] is velocity. Given,\[h=6.626\times {{10}^{-34}}J-s,\,\,m=1\,\,kg\], \[v=10\,\,m/s\] \[\therefore \] \[\lambda =\frac{6.626\times {{10}^{-34}}}{1\times 10}=6.626\times {{10}^{-35}}m\]
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