2. Solved Papers
  3. JCECE Engineering

JCECE Engineering JCECE Engineering Solved Paper-2003

  • question_answer
    Domain of the function\[\sin \log \left( \frac{\sqrt{4-{{x}^{2}}}}{1-x} \right)\]is:

    A) \[[-2,\,\,1]\]                      

    B) \[(-2,\,\,1)\]

    C) \[[-2,\,\,1)\]                      

    D) \[(-2,\,\,1]\]

    Correct Answer: B

    Solution :

    Key Idea: \[\log x\] is defined for\[x>0\]. Let          \[f(x)=\sin \log \left( \frac{\sqrt{4-{{x}^{2}}}}{1-x} \right)\] For domain of\[f(x)\],                 \[\frac{\sqrt{4-{{x}^{2}}}}{1-x}>0\] \[\Rightarrow \]               \[4-{{x}^{2}}>0\]and\[1-x>0\] \[\Rightarrow \]               \[-2<x<2\]and\[x<1\] \[\Rightarrow \]               \[x\in (-2,\,\,1)\]


You need to login to perform this action.
You will be redirected in 3 sec spinner