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JCECE Engineering JCECE Engineering Solved Paper-2003

  • question_answer
    A line passes through \[(2,\,\,2)\] and is perpendicular to the line \[3x+y=3\], its \[y-\]intercept is:

    A) \[1/3\]                                 

    B)  \[2/3\]

    C)  \[1\]                                    

    D)  \[4/3\]

    Correct Answer: D

    Solution :

    The equation of a line passing through a point \[(2,\,\,2)\] and is perpendicular to the line \[3x+y=3\]is                 \[y-2=\frac{1}{3}(x-2)\] \[\Rightarrow \]               \[3y-6=x-2\] \[\Rightarrow \]               \[x-3y+4=0\] Since, this line intercept the \[y-\]axis,\[i.e.,\]\[x=0\] \[\Rightarrow \]               \[-3y+4=0\Rightarrow y=\frac{4}{3}\]


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