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JCECE Engineering JCECE Engineering Solved Paper-2003

  • question_answer
    The number of divisors of \[9600\] including \[1\] and \[9600\] are:

    A) \[60\]                                   

    B) \[58\]

    C) \[48\]                                   

    D) \[46\]

    Correct Answer: C

    Solution :

    \[9600={{2}^{7}}\times 3\times {{5}^{2}}\] \[\therefore \]The number of divisors                 \[=(7+1)(1+1)(2+1)\] \[=8\times 2\times 3\]                 \[=48\]


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