A) \[C{{H}_{3}}C{{H}_{2}}CHO\]
B) \[C{{H}_{3}}C{{H}_{2}}COOH\]
C) \[C{{H}_{3}}-C(OH)=CHOH\]
D) \[C{{H}_{3}}COC{{H}_{3}}\]
Correct Answer: D
Solution :
Key Idea: \[{{H}_{2}}O\] adds across triple bond in presence of \[H{{g}^{2+}}\] salt. \[\underset{propyne-1}{\mathop{C{{H}_{3}}-C\equiv CH+{{H}_{2}}O}}\,\xrightarrow{{{H}^{+}}/H{{g}^{2+}}}\] \[\underset{acetone}{\mathop{C{{H}_{3}}-\overset{\begin{smallmatrix} O \\ || \end{smallmatrix}}{\mathop{C}}\,-C{{H}_{3}}}}\,\]
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