JCECE Engineering JCECE Engineering Solved Paper-2003

  • question_answer
    An ideal gas at \[{{27}^{o}}C\] is compressed adiabatically to \[\frac{8}{27}\] of its original volume. The rise in temperature will be\[\left( \gamma =\frac{5}{3} \right)\].

    A) \[{{480}^{o}}C\]                               

    B) \[{{275}^{o}}C\]

    C)  \[{{450}^{o}}C\]                              

    D)  \[{{375}^{o}}C\]

    Correct Answer: D

    Solution :

    When a system undergoes a change under the condition that no exchange of heat takes place between system and surrounding them such a process is called an adiabatic one. The relation between temperature \[(T)\], volume \[(V)\] and ratio of specific heats \[(\gamma )\] is                 \[T{{V}^{\gamma -1}}=\]constant \[\therefore \]  \[\frac{T'}{T}={{\left( \frac{V}{V'} \right)}^{\gamma -1}}={{\left( \frac{27}{8} \right)}^{\frac{5}{3}-1}}={{\left( \frac{27}{8} \right)}^{\frac{2}{3}}}\] \[\Rightarrow \]               \[\frac{T'}{T}={{\left( \frac{3}{2} \right)}^{2}}=\frac{9}{4}\] \[\Rightarrow \]               \[T'=\frac{9}{4}T=\frac{9}{4}\times (273+27)\] \[\Rightarrow \]               \[T'=\frac{9}{4}\times 300=675\,\,K\]


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