A) become four times
B) become half
C) become two times
D) remain unchanged
Correct Answer: B
Solution :
Momentum of a particle is related to de-Broglie wavelength through the relation given by \[p=\frac{h}{\lambda }\] where \[h\] is Planck's constant. or \[\lambda =\frac{h}{p}\] or \[\lambda \propto \frac{1}{p}\] \[i.e.,\] de-Broglie wavelength is inversely proportional to the momentum of the particle, so, if momentum is doubled, then de-Broglie wavelength will become half.
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