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JCECE Engineering JCECE Engineering Solved Paper-2002

  • question_answer
    The least integer \[k\] which makes roots of the equation \[{{x}^{2}}+5x+k=0\] become imaginary, is:

    A) \[4\]                                     

    B) \[5\]

    C) \[6\]                                     

    D) \[\frac{25}{4}\]

    Correct Answer: D

    Solution :

    Key Idea: For imaginary roots, the discriminant will be negative. Given quadratic equation is                 \[{{x}^{2}}+5x+k=0\] Since, roots are imaginary \[\therefore \]  Discriminant,\[D<0\] \[\Rightarrow \]               \[{{(5)}^{2}}-4k<0\] \[\Rightarrow \]               \[k<\frac{25}{4}\] \[\therefore \]Least value of \[k\] is\[\frac{25}{4}\].


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