A) positive and non-zero
B) negative and non-zero
C) zero
D) none of the above
Correct Answer: C
Solution :
Key Idea: No displacement of particle takes place on a complete circular path. Work done by a particle is defined as scalar product of force \[(\overrightarrow{\mathbf{F}})\] and displacement \[(\overrightarrow{\mathbf{s}})\] \[W=\overset{\to }{\mathop{\mathbf{F}}}\,\cdot \overset{\to }{\mathop{\mathbf{s}}}\,=Fs\cos \theta \] In a complete circular motion,the displacement undergone by particle is zero, hence work done is zero.
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