A) 35
B) 30
C) 25
D) 20
Correct Answer: C
Solution :
Let the values of 9 items be\[{{x}_{1}},{{x}_{2}},....,{{x}_{9}},\]we have \[15=\frac{{{x}_{1}}+{{x}_{2}}+...+{{x}_{9}}}{9}\] \[\Rightarrow \] \[{{x}_{1}}+{{x}_{2}}+....+{{x}_{9}}=15\times 9=135\] ?(i) Let\[{{x}_{10}}\]be the 10th item. The mean of \[{{x}_{1}},{{x}_{2}},.....,{{x}_{9}},{{x}_{10}}\]is 16. i.e., \[16=\frac{{{x}_{1}}+{{x}_{2}}+....+{{x}_{9}}+{{x}_{10}}}{10}\] \[\Rightarrow \]\[{{x}_{1}}+{{x}_{2}}+....+{{x}_{9}}+{{x}_{10}}=160\] [From Eq. (i)] \[\Rightarrow \] \[135+{{x}_{10}}=160\] \[\Rightarrow \] \[{{x}_{10}}=160-135=25\]
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