A) \[-25.48\text{ }kJmo{{l}^{-1}}\]
B) \[+25.48\text{ }kJ\text{ m}o{{l}^{-1}}\]
C) \[-36.73kJmo{{l}^{-1}}\]
D) \[+36.73kJmo{{l}^{-1}}\]
Correct Answer: D
Solution :
\[{{H}_{2}}O(l){{H}_{2}}O(g)\] \[\Delta H_{vap}^{o}=40.66\,kJ\,mo{{l}^{-1}}\] \[\Delta {{n}_{g}}=1-0=1\] \[\Delta H{}^\circ =\Delta E{}^\circ +\Delta {{n}_{g}}RT\] \[40.66=\Delta E{}^\circ +1\times 8.314\times {{10}^{-3}}\times 473\] \[40.66=\Delta E{}^\circ +3.93\] \[\Delta E{}^\circ =+36.73\,kJ\,mo{{l}^{-1}}\]
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