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JAMIA MILLIA ISLAMIA Jamia Millia Islamia Solved Paper-2013

  • question_answer
    At\[90{}^\circ C,\]the following equilibrium is established\[{{H}_{2}}(g)+S(s){{H}_{2}}S(g);\]\[{{K}_{c}}=6.8\times {{10}^{-2}}\] If 0.20 mole hydrogen and 1.0 mole of sulphur are heated to\[90{}^\circ C\]in a 1.0 L vessel, what will be the partial pressure of\[{{H}_{2}}S\]at equilibrium?

    A)  0.25 atm                             

    B)  0.38 atm

    C)  0.46 atm                             

    D)  0.56 atm

    Correct Answer: B

    Solution :

                                      \[{{H}_{2}}(g)+S(s){{H}_{2}}S(g);\]              \[{{K}_{c}}=6.8\times {{10}^{-2}}\] Initial            0.20                        0 Atequiation \[(0.20-x)~\]                       \[x\]                 \[{{K}_{c}}=6.8\times {{10}^{-2}}=\frac{[{{H}_{2}}S]}{{{H}_{2}}}\]                 \[6.8\times {{10}^{-2}}=\frac{x}{0.20-x}\]                 \[x=1.273\times {{10}^{-2}}mol\,{{L}^{-1}}\]                 \[{{p}_{{{H}_{2}}S}}=\left( \frac{n}{v} \right)RT\]                 \[=(1.273\times {{10}^{-2}})\times 0.0821\times 363\] \[=0.38\text{ }atm\]


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