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JAMIA MILLIA ISLAMIA Jamia Millia Islamia Solved Paper-2013

  • question_answer
    In the following reaction, we start with 2 moles of\[{{N}_{2}}\]and 5 moles of\[{{H}_{2}}\]exerting a total prssure of 7 aim at a given temperature in a closed vessel. When 50% of\[{{N}_{2}}\]s converted into\[N{{H}_{3}},\] partial pressure of\[N{{H}_{3}}\]is \[{{N}_{2}}+3{{H}_{2}}\xrightarrow[{}]{{}}2N{{H}_{3}}\]

    A)  2.8 atm               

    B)  2atm

    C)  3.2 atm               

    D)  4 atm

    Correct Answer: B

    Solution :

                                                    \[{{N}_{2}}+3{{H}_{2}}\xrightarrow[{}]{{}}2N{{H}_{3}}\] Initial moles                 \[2~~~~~~~~~~5~~~~~~~~~~~~~0\] reacted (50% \[{{N}_{2}}\])       \[~1~~~~~~~~~3~~~~~~~~~~~~~~2\] Left moles.                    \[1~~~~~~~~~2~~~~~~~~~~~~~~2\] Total number of moles of\[{{N}_{2}}{{H}_{2}}\]and\[N{{H}_{3}}\]left \[=1+2+2=5\] Initial moles = 7 pressure at initials =7 atm pressure at equilibrium =5 atm Partial pressure of\[N{{H}_{3}}=\frac{2}{5}\times 5=2\,atm\]


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