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JAMIA MILLIA ISLAMIA Jamia Millia Islamia Solved Paper-2013

  • question_answer
    The velocities of light in two different mediums are\[2\times {{10}^{8}}\text{ }m/s\]and \[2.5\times {{10}^{8}}m/s\]respectively. The critical angle for these medium is

    A)  \[{{\sin }^{-1}}\left( \frac{1}{5} \right)\]                               

    B)  \[{{\sin }^{-1}}\left( \frac{4}{5} \right)\]

    C)  \[{{\sin }^{-1}}\left( \frac{1}{2} \right)\]                               

    D)  \[{{\sin }^{-1}}\left( \frac{1}{4} \right)\]

    Correct Answer: B

    Solution :

                    Critical angle is given by \[\sin C=\mu =\frac{{{v}_{1}}}{{{v}_{2}}}\]                 \[=\frac{2\times {{10}^{8}}}{2.5\times {{10}^{8}}}=\frac{20}{25}=\frac{4}{5}\] \[\Rightarrow \]               \[C={{\sin }^{-1}}\left( \frac{4}{5} \right)\]


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