A) 22.2 % increase
B) 22.2% decrease
C) 18.2% decrease
D) 18.2% increase
Correct Answer: A
Solution :
Speed of sound\[=v\](say) Speed of source = speed of observer\[=\frac{v}{10}\] Let natural frequency of sound\[=n\] Apparent frequency of sound \[n=n\left[ \frac{v-{{v}_{0}}}{v-{{v}_{s}}} \right]\] Since, source is moving in the direction of sound and observer moving towards, sources then \[{{v}_{0}}=\frac{v}{10}\]and\[{{v}_{s}}=\frac{v}{10}\] \[n=n\left[ \frac{v+\frac{v}{10}}{v-\frac{v}{10}} \right]=\frac{\frac{11v}{10}}{\frac{9v}{10}}\] \[n=\frac{11}{9}n\] \[n-n=\frac{11}{9}n-n=\frac{2}{9}n\] \[\frac{n-n}{n}=\frac{2}{9}\] \[\frac{n-n}{n}\times 100=\frac{2}{9}\times 100%\] \[=\frac{200}{9}%=22.2%\]
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