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JAMIA MILLIA ISLAMIA Jamia Millia Islamia Solved Paper-2013

  • question_answer
        The area of cross-section of a wire of length 1.1 m is\[1m{{m}^{2}}\]. It is leaded with 1 kg of Youngs    modulus    of   copper   is\[1.1\times {{10}^{11}}N{{m}^{-2}},\]then the increase in length will be (if\[g=10m{{s}^{-2}}\])

    A)  0.01 mm             

    B)  0.075 mm

    C)  0.1 mm               

    D)  0.15mm

    Correct Answer: C

    Solution :

                    Increase in length \[l=\frac{mgL}{AY}\] \[=\frac{1\times 10\times 1.1}{1.1\times {{10}^{11}}\times {{10}^{-6}}}m=0.1\,mm\]?(i)


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