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JAMIA MILLIA ISLAMIA Jamia Millia Islamia Solved Paper-2013

  • question_answer
        The work done by a force\[F=(-6{{x}^{3}})iN,\]in displacing a particle from\[x=4\text{ }m\]to \[x=-2m\] is

    A)  360 J                                    

    B)  240 J

    C)  \[-240J\]           

    D)  \[-360J\]

    Correct Answer: D

    Solution :

                    Work done \[=\int{F.dx}\] Given,      \[F=-(6{{x}^{3}})iN\] \[\therefore \]  \[W=-\int_{-2}^{4}{6{{x}^{3}}dx}\]                 \[W=-6\left[ \frac{{{x}^{4}}}{4} \right]_{-2}^{4}\]                 \[W=-\frac{6}{4}[{{(4)}^{4}}-{{(2)}^{4}}]\]                 \[W=-1.5\times 240=-360\,J\]


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