A) \[{{e}^{x}}\cot x+C\]
B) \[{{e}^{x}}\cos ecx+C\]
C) \[-{{e}^{x}}\cot x+C\]
D) \[-{{e}^{x}}\cos ecx+C\]
Correct Answer: C
Solution :
Let\[{{x}_{1}},{{x}_{2}}\in R\]such that\[{{x}_{1}}<{{x}_{2}}\]. Then,\[{{x}_{1}}<{{x}_{2}}\] \[\Rightarrow \] \[f({{x}_{1}})<f({{x}_{2}})\] (\[\because \]\[f\]is an increasing function) \[\Rightarrow \] \[g\{f({{x}_{1}})\}<g\{f({{x}_{2}})\}\] (\[\because \]is an increasing function) \[\Rightarrow \] \[gof({{x}_{1}})<gof({{x}_{2}})\] Hence,\[gof\]is an increasing function.
You need to login to perform this action.
You will be redirected in
3 sec
