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JAMIA MILLIA ISLAMIA Jamia Millia Islamia Solved Paper-2012

  • question_answer
    If\[\Delta G=46.06\text{ }kcal/mol,\]\[{{K}_{p}}\]at 300 K is

    A)  \[{{10}^{-33.33}}\]                                         

    B)  \[{{10}^{-23.03}}\]

    C)  \[{{10}^{-50.12}}\]                                         

    D)  \[{{10}^{+33.33}}\]

    Correct Answer: A

    Solution :

                    \[{{K}_{p}}={{e}^{-\Delta G/RT}}={{10}^{-\Delta G/2.303RT}}\] \[{{K}_{p}}={{10}^{-46.06/1.99\times {{10}^{-3}}\times 300\times 2.303}}\] \[{{K}_{p}}={{10}^{-33.33}}\]


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