A) \[HN{{O}_{3}}\]
B) \[C{{l}_{2}}\]
C) \[FeC{{l}_{3}}\]
D) All of these
Correct Answer: D
Solution :
\[HN{{O}_{3}},C{{l}_{2}}\]and\[FeC{{l}_{3}}\]can accept electrons and can decrease their oxidation numbers and hence, all these substances act as oxidizing agents. \[\overset{+5}{\mathop{HN{{O}_{3}}}}\,\xrightarrow[{}]{{}}\overset{+4}{\mathop{N{{O}_{2}}}}\,\]or \[\overset{+2}{\mathop{NO}}\,\] \[\overset{0}{\mathop{C{{l}_{2}}}}\,\xrightarrow[{}]{{}}\overset{-1}{\mathop{2Cl}}\,\] \[\overset{+3}{\mathop{FeC{{l}_{3}}}}\,\xrightarrow[{}]{{}}\overset{+2}{\mathop{FeC{{l}_{2}}}}\,\]
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