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JAMIA MILLIA ISLAMIA Jamia Millia Islamia Solved Paper-2012

  • question_answer
        A monoatomic gas supplied the heat Q very slowly keeping the pressure constant. The work done by the gas will be

    A)  \[\frac{2}{3}Q\]                                              

    B)  \[\frac{3}{5}Q\]

    C)  \[\frac{2}{5}Q\]                                              

    D)  \[\frac{1}{5}Q\]

    Correct Answer: A

    Solution :

                    For monoatomic gas at constant pressure \[\frac{\Delta U}{Q}=\frac{1}{3}\]or\[\Delta U=\frac{Q}{3}\] Now, applying first law of thermodynamics \[W=\Delta Q-\Delta U\]                 \[=Q-\frac{Q}{3}=\frac{2Q}{3}\]


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