JAMIA MILLIA ISLAMIA Jamia Millia Islamia Solved Paper-2012

  • question_answer
        If work function of a metal is 4.2 eV, the cut off wavelength is

    A)  \[8000\text{ }\overset{o}{\mathop{\text{A}}}\,\]         

    B)  \[7000\text{ }\overset{o}{\mathop{\text{A}}}\,\]

    C)  \[\text{1472 }\overset{o}{\mathop{\text{A}}}\,\]         

    D)  \[\text{2950 }\overset{o}{\mathop{\text{A}}}\,\]

    Correct Answer: D

    Solution :

                    Suppose the cut-off wavelength is represented by\[{{\lambda }_{0}}\] So, \[\frac{hc}{{{\lambda }_{0}}}=\]work function \[={{W}_{0}}\]                 \[\frac{hc}{{{\lambda }_{0}}}=4.2\times 1.6\times {{10}^{-19}}\]                 \[{{\lambda }_{0}}=\frac{6.6\times {{10}^{-34}}\times 3\times {{10}^{8}}}{4.2\times 1.6\times {{10}^{-19}}}\]                 \[=2946\times {{10}^{-10}}m\approx 2950\,\overset{o}{\mathop{\text{A}}}\,\]


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