A) 2.9cm
B) 3.9cm
C) 2.35cm
D) 2cm
Correct Answer: C
Solution :
The radius of circular path \[r=\frac{mv}{eB}=\frac{v}{\left( \frac{e}{m} \right)B}\] ?.(i) Given,\[e/m\]of electron \[=1.7\times {{10}^{11}}C/kg,v=6\times {{10}^{7}}m/s\] and \[B=1.5\times {{10}^{-2}}T\] So,\[r=\frac{6\times {{10}^{7}}}{1.7\times {{10}^{11}}\times 1.5\times {{10}^{-2}}}=2.35\times {{10}^{-2}}m\]\[=2.35\text{ }cm\]You need to login to perform this action.
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