A) \[\frac{{{x}^{2}}}{16}+\frac{{{y}^{2}}}{25}=1\]
B) \[\frac{{{x}^{2}}}{25}+\frac{{{y}^{2}}}{16}=1\]
C) \[\frac{{{x}^{2}}}{9}+\frac{{{y}^{2}}}{25}=1\]
D) None of these
Correct Answer: A
Solution :
Given, centre (0, 0), focus (0, 3) and\[b=5\] Focus (0, 3) \[\Rightarrow \] \[be=3\] \[\Rightarrow \] \[e=\frac{3}{5}\] \[\therefore \] \[a=b\sqrt{1-{{e}^{2}}}=4\] \[\therefore \]Required equation is \[\frac{{{x}^{2}}}{16}+\frac{{{y}^{2}}}{25}=1\]
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