A) \[n>6\]
B) \[n>7\]
C) \[n<6\]
D) None of these
Correct Answer: A
Solution :
Since, \[^{n}{{C}_{3}}{{+}^{n}}{{C}_{4}}{{>}^{n+1}}{{C}_{3}}\] \[\Rightarrow \] \[^{n+1}{{C}_{4}}{{>}^{n+1}}{{C}_{3}}\] \[\Rightarrow \] \[\frac{^{n+1}{{C}_{4}}}{^{n+1}{{C}_{3}}}>1\] \[\Rightarrow \] \[\frac{n-2}{4}>1\] \[\Rightarrow \] \[n>6\]
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