JAMIA MILLIA ISLAMIA Jamia Millia Islamia Solved Paper-2011

  • question_answer
        The number of gram-molecules of oxygen which are present in\[6.022\times {{10}^{24}}CO\]molecules is

    A)  10 g-molecule                  

    B)  5 g-molecule

    C)  1 g-molecule                    

    D)  0.5 g-molecule

    Correct Answer: B

    Solution :

                    Number of oxygen atoms = Number of CO molecules                 \[=6.022\times {{10}^{24}}\] Number of oxygen molecules \[=\frac{1}{2}\times \]No. of oxygen atoms \[=\frac{1}{2}\times 6.022\times {{10}^{24}}=3.011\times {{10}^{24}}\] Number of g-molecules of oxygen \[=\frac{3.011\times {{10}^{24}}}{6.022\times {{10}^{23}}}=\]5 g-molecule


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