A) \[Pb\]is more electropositive than\[Ge\]
B) ionisation potential of lead is less than that of\[Ge\]
C) ionic radii of\[P{{b}^{2+}}\]and\[P{{b}^{4+}}\]are larger than those of\[G{{e}^{2+}}\]and\[G{{e}^{4+}}\]
D) more pronounced inert pair effect in lead than in Ge
Correct Answer: D
Solution :
\[Ge(IV)\]is more stable than\[Ge(II)\]. Therefore, \[Ge(II)\]compounds are powerful reducing agents.\[Pb(IV)\]is less stable than\[Pb(II)\]. Therefore,\[Pb(IV)\]compounds are powerful oxidising agents. This is due to inert pair effect, due to which the +2 oxidation state becomes more stable on moving down the group.
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