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JAMIA MILLIA ISLAMIA Jamia Millia Islamia Solved Paper-2011

  • question_answer
        A parallel plate capacitor is moving with a velocity of\[25\text{ }m{{s}^{-1}}\]through a uniform magnetic field of 1.5 T as shown in figure. If the electric field within the capacitor plates is\[175\text{ }N{{C}^{-1}}\] and plate area is\[25\times {{10}^{-7}}{{m}^{2}},\]then the magnetic force experienced by positive charge plate is

    A)  \[1.45\times {{10}^{-13}}N\]

    B)  zero

    C)  \[8.67\times {{10}^{-15}}N\]

    D)  \[3.87\times {{10}^{-15}}N\]

    Correct Answer: A

    Solution :

                    Electric field in between the capacitor plates is given by \[E=\frac{q}{{{\varepsilon }_{0}}A}\] or            \[q={{\varepsilon }_{0}}A\times E\] \[=8.85\times {{10}^{-12}}\times 25\times {{10}^{-7}}\times 175\] \[=3.87\times {{10}^{-15}}C\] Magnetic force experienced by +ye plate is, \[{{F}_{m}}=qvB=1.45\times 10{{~}^{-13}}N\] in a direction out of plane of paper.


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