JAMIA MILLIA ISLAMIA Jamia Millia Islamia Solved Paper-2011

  • question_answer
        A circular ring having uniformly distributed mass m and radius r is as shown in the figure. If a point mass m is taken slowly from A to B, then work done by the external agent will be

    A)  \[-\frac{GMm}{R}\left[ \frac{1}{\sqrt{2}}-\frac{1}{\sqrt{5}} \right]\]      

    B)  \[\frac{GMm}{R}\times \frac{1}{\sqrt{5}}\]

    C)  \[\frac{GMm}{R}\left[ \frac{1}{\sqrt{2}}-\frac{1}{\sqrt{5}} \right]\]        

    D)  \[\frac{GMm}{R}\left[ \frac{1}{\sqrt{10}} \right]\]

    Correct Answer: C

    Solution :

                    PE of the system when point mass is at A, is \[{{U}_{i}}=-\frac{GMm}{\sqrt{2}R}\] PE of system when point mass is at B, is                 \[{{U}_{f}}=-\frac{GMm}{\sqrt{5}R}\] Work done by gravity force on point mass as it moves from A to B, is \[{{W}_{gravitational}}=-dU=-({{U}_{f}}-{{U}_{i}})\]                 \[=\frac{GMm}{R}\left[ \frac{1}{\sqrt{5}}-\frac{1}{\sqrt{2}} \right]\] From work-energy theorem,                 \[dK=0={{W}_{grav.}}+{{W}_{ext.}}\]                 \[{{W}_{ext.}}=-{{W}_{grav.}}\]                 \[=\frac{GMm}{R}\left[ \frac{1}{\sqrt{2}}-\frac{1}{\sqrt{5}} \right]\]


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