A) \[\frac{8e}{{{\varepsilon }_{0}}}\]
B) \[\frac{16e}{{{\varepsilon }_{0}}}\]
C) \[\frac{e}{{{\varepsilon }_{0}}}\]
D) zero
Correct Answer: D
Solution :
\[\phi =\frac{\Sigma q}{{{\varepsilon }_{0}}}=0,\]ie, net charge on dipole is zero.
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