\[X\]is
A) \[SiC\]
B) \[{{H}_{2}}S{{O}_{4}}\]
C) \[KMn{{O}_{4}}\]
D) \[Fe/HCl\]
Correct Answer: D
Solution :
Key Idea: Reduction of\[N{{O}_{2}}\]group to\[N{{H}_{2}}\]group is taking place by\[Fe\,\,A/Cl\].
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