A) 0.083 mol
B) 0.952 mol
C) 0.481 mol
D) 0.140 mol
Correct Answer: D
Solution :
Key Idea: \[Moles=\frac{mass}{molecular\text{ }weight}\] Given, mass of \[A{{l}_{2}}{{(S{{O}_{4}})}_{3}}=50\,g\] molecular mass of \[A{{l}_{2}}{{(S{{O}_{4}})}_{3}}=342\,g\] \[\therefore \] Moles of \[A{{l}_{2}}{{(S{{O}_{4}})}_{3}}=\frac{50}{342}=0.14\,mol\]
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