A) \[\int_{0}^{\infty }{V}dx\]
B) \[\frac{dV}{dx}\]
C) \[-\frac{dV}{dx}\]
D) \[-V\frac{dV}{dx}\]
Correct Answer: C
Solution :
The electric Held intensity at a point in an electric field in a given direction is equal to he negative potential gradient in that direction ie, \[E=-\frac{dV}{dx}\] The negative sign signifies that the potential decreases in the direction of the electric field. Note: It is evident from above relation, that the electric field E can also be expressed in the unit volt / metre or\[V{{m}^{-1}}\] Thus, \[1\,N{{C}^{-1}}=1\,V{{m}^{-1}}\]
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