A) \[\frac{1}{18}\]
B) \[\frac{1}{6}\]
C) \[\frac{5}{216}\]
D) \[\frac{1}{36}\]
Correct Answer: D
Solution :
Given, number of red beads = 6 Number of white beads = 30 Total number of beads \[=6+30=36\] Probability of drawing red beads in 2 successive trials \[=\frac{6}{36}\times \frac{6}{36}\] \[=\frac{1}{36}\] [ \[\because \] events are independent]
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