A) \[-300\,R\,\ln \,10\]
B) \[300\,R\,\ln \,10\]
C) \[18\]
D) \[-18\]
Correct Answer: A
Solution :
Given, \[{{V}_{1}}=2L\] \[{{V}_{2}}=20\,L\] \[T=300K\] \[{{p}_{2}}=1\,\text{bar}\] Work done for ideal gas expands isothermally and reversibly \[\Rightarrow \] \[W=-2303RT\,\log \frac{{{V}_{2}}}{{{V}_{1}}}\] \[\Rightarrow \] \[W=-RT\,\ln \,\frac{{{V}_{2}}}{{{V}_{1}}}\] \[\Rightarrow \] \[W=-R\times 300\,\ln \frac{20}{2}\] \[\Rightarrow \] \[W=-300\,R\,\ln \,10\]
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