A) \[27.2\,eV\]
B) \[13.6\,\,eV\]
C) \[6.8\,eV\]
D) \[3.4\,eV\]
Correct Answer: D
Solution :
Energy of electron in nth orbit of H-atom is given by \[{{E}_{n}}=-\frac{13.6}{{{n}^{2}}}eV/\text{atom}\] For \[n=2\] \[{{E}_{2}}=\frac{-13.6}{{{(2)}^{2}}}=-3.4\,eV\]
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