A) \[{{10}^{10}}\]
B) \[{{10}^{20}}\]
C) \[{{10}^{40}}\]
D) \[{{10}^{60}}\]
Correct Answer: C
Solution :
\[A(S)+2{{B}^{+}}(aq)\xrightarrow{{}}{{A}^{2+}}(aq)+2B(s)\] Oxidation \[A(s)\xrightarrow{{}}{{A}^{2+}}(aq)+2{{e}^{-}}\] Reduction\[2{{B}^{+}}(aq)+2{{e}^{-}}\xrightarrow{{}}2B(s)\] Here, \[n=2\] \[{{E}^{o}}=1.18\,V\] \[{{K}_{eq}}=?\] \[\because \]\[\log \,{{K}_{eq}}=\frac{n{{E}^{o}}F}{RT}\] \[\left[ \frac{F}{RT}=\frac{1}{0.059} \right]\] \[\therefore \] \[\log \,{{K}_{eq}}=\frac{2\times 1.18\times 1}{0.059}\] \[\therefore \] \[\log \,{{K}_{eq}}=40\]or \[\,{{K}_{eq}}={{10}^{40}}\]
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