J & K CET Engineering J and K - CET Engineering Solved Paper-2015

  • question_answer
    A bullet fired from a rifle loses \[20%\]of its speed while passing through a wooden plank. Then, minimum number of wooden planks required to completely stop the bullet is

    A) \[3\]      

    B) \[5\]

    C) \[15\]     

    D) \[25\]

    Correct Answer: A

    Solution :

    Let n number of wooden planks are required to Completely stop the bullet. Speed of the bullet after passing through 1 st block \[{{v}_{1}}=v-v\times \frac{20}{100}=v-\frac{v}{5}=\frac{v}{5}v\] Speed of the bullet after passing through 2nd block \[{{v}_{2}}=\frac{4}{5}\left( v-\frac{v}{5} \right)={{\left( \frac{4}{5} \right)}^{n}}v\] Similarly, speed of the block after passing through 3rd block \[{{v}_{n}}={{\left( \frac{4}{5} \right)}^{n}}v\] For  \[{{v}_{n}}\to 0,\,\,n\to \infty \] Minimum value of 22 given in the question is\[n=3\].


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