A) \[0.25\text{ }m\]
B) \[0.5\text{ }m\]
C) \[0.75\text{ }m\]
D) zero
Correct Answer: D
Solution :
Displacement in the nth second is given by \[{{S}_{n}}=4+\frac{a}{2}(2n-1)\] In this problem retardation is involved. Thus, the equation becomes \[{{S}_{n}}=4-\frac{a}{2}(2n-1)\] Given \[u=9\text{ }m/s,\text{ }a=2\text{ }m/s\] \[n=5\] \[\Rightarrow \] \[{{S}_{5}}=9-\frac{2}{2}(2\times 5-1)\] \[=9-9=0\]
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