A) \[1/R\]
B) \[4/R\]
C) \[9/R\]
D) \[16/R\]
Correct Answer: B
Solution :
As we know that \[\frac{1}{\lambda }=R\left( \frac{1}{n_{1}^{2}}-\frac{1}{n_{2}^{2}} \right)\] For Balmer series, \[{{n}_{1}}=2,\,\,{{n}_{2}}=3,4.....\] Corresponding to series limit, \[{{n}_{2}}=\infty \] \[\frac{1}{\lambda }=R\left( \frac{1}{4}-\frac{1}{{{\infty }^{2}}} \right)\Rightarrow \lambda =\frac{4}{R}\]
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