J & K CET Engineering J and K - CET Engineering Solved Paper-2014

  • question_answer
    A manufacturer has \[500\text{ }L\]of a \[10%\]solution of acid, find the range of 40% acid to be added to it y such that the acid content in the resultant mixture will be more than \[15%\] but less than \[20%\] .

    A)  More than \[250\text{ }L\]and less than \[~300\]               

    B)  More than \[300\text{ }L\] and less than \[400\]

    C)  More than \[100\text{ }L\] and less than \[250\]

    D)  More than \[250\text{ }L\]and less than \[350\]

    Correct Answer: C

    Solution :

    Let x litre of 40% acid solution is required to be added. Then, Total mixture \[=(x+500)L\] \[\therefore \] \[40%\] of \[x+10%\] of \[500>15%\] of \[(x+500)\] \[\Rightarrow \]   \[\frac{40x}{100}+\frac{10\times 500}{100}>\frac{15}{100}\times (x+500)\] \[\Rightarrow \]  \[40x+5000>15x+7500\] \[\Rightarrow \]  \[25x>2500\] \[\Rightarrow \] \[x>100\] ?..(i) Also, \[40%\] of \[x+10%\] of \[500<20%\] of \[(x+500)\] \[\Rightarrow \]   \[\frac{40}{100}x+\frac{10}{100}\times 500<\frac{20}{100}(x+500)\] \[\Rightarrow \] \[40x+5000<20x+10000\] \[\Rightarrow \] \[20x<5000\] \[\Rightarrow \] \[x<250\] ?..(ii) From Eqs. (i) and (ii), we get required range, is more than \[100L\]and less than \[250L\].


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